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4x^2-60x+224=0
a = 4; b = -60; c = +224;
Δ = b2-4ac
Δ = -602-4·4·224
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4}{2*4}=\frac{56}{8} =7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4}{2*4}=\frac{64}{8} =8 $
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